Find the three consecutive even integers whose sum is 432

Answer 1

In this problem, we will make the equations for the three consecutive even integers: Let x be the integer.

x

x+2

x+4

Now we will plug those three equations in to equal to 432.

x+(x+2)+(x+4)=432

Then go ahead and add the like terms together to get to this next step:

3x+6=432

Now we will subtract 6 from both sides to cancel out the +6 on the left side of the equation:

3x+6-6=432-6.

So you will get to this point: 3x=426. Now divide the 3 on both sides to solve for x to get our first smallest even integer number which is x=142.

Now, we have x=142 which is the smallest one of the three consecutive even integer answer. We will plug in x=142 to the last two equations which are x+2 and x+4.

142+2=144

142+4=146

The three consecutive even integers are 142, 144, 146 as the answer!