Stochiometry Problem

Question

Bismuth oxide reacts with carbon to form bismuth metal:

 

Bi₂O₃(s) + 3C(s) → 2Bi(s) + 3CO(g)

 

When 28.0 g of Bi₂O₃ reacts with excess carbon,

 

(a) how many moles of Bi form?

 

(b) how many grams of CO form?

Answer 1

28.0 g Bi2O3 x 1 mole Bi2O3/457 g = 0.0613 moles Bi2O3

moles Bi formed = 0.0613 moles Bi2O3 x 2 moles Bi/1 mole Bi2O3 = 0.1226 moles Bi = 0.123 moles Bi (3 significant figures)

grams CO formed = 0.0613 moles Bi2O3 x 3 moles CO/1 mole Bi2O3 x 28 g CO/mole CO = 5.15 g CO