Kisla K.

asked • 09/26/19

An isosceles trapezoid ABCD has bases AD=17 cm, BC=5 cm, and side AB=10 cm. Through the vertex B there is a line, which bisects diagonal AC and intersects AD at point M. What is the area of BDM?

No videos please, only written explanation.

Brenda D.

tutor
Since BD is a diagonal across the Isosceles Trapezoid, the height of the trapezoid, determined using the Pythagorean Theorem, is also the height of triangle BDM. All you need to do is to determine the base of BDM by difference since it shares a portion of the Trapezoid's base. It is still a good practice to draw yourself a figure to see the relationship between the Trapezoid and the Triangle formed within. For example dropping a height from point C down to line AD form a right triangle that is a perfect Pythagorean triple.
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09/28/19

1 Expert Answer

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Victoria V. answered • 09/26/19

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Math Teacher: 20 Yrs Teaching/Tutoring CALC 1, PRECALC, ALG 2, TRIG

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I know you did not want a video, but I just needed for you to be able to see the figure. It should show up above, even if you do not play the video.


If the figure is drawn accurately, on a grid, this is what you see (see video picture above).


Triangle BDM is the one outlined in orange. Area of a triangle = 1/2 b h so A = (0.5)(12)(8) = 48 sq cm

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