How many mL of a 2.00M NaOH solution would you need to neutralize 12.7 mL of a 1.75M HCl solution?

Answer 1

NaOH + HCl —> NaCl + H₂O ... balanced eq

mol HCl present = 0.0127 L x 1.75 mol/L = 0.0222 mol HCl

moles NaOH needed = 0.0222 moles NaOH

mls NaOH: 2.00 mol/L * (xL) = 0.0222 moles and x = 0.0111 L

0.0111 L x 1000 ml/L = 11.1 mls NaOH needed