The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of intersection of the diagonals and the side of the rhombus?

Question

The area of the rhombus is 540 cm²; the length of one of its diagonals is 4.5 dm. What is the distance between the point of intersection of the diagonals and the side of the rhombus?

Answer 1

Draw and label a diagram!!

540 cm² = (p cm)(q cm) / 2

1080 cm² = 45 cm (p cm)

24 cm = p

The four right triangles have legs of 12 and 22.5

The distance to a side of the rhombus is the length of the altitude to the hypotenuse..