Finding freezing point

Question

One mole of sucrose C​​H​​O​​, a common sweetener is added to 1000 grams of water. What is the final freezing point of the solution in degrees Celsius (assuming the substance dissolves completely)?

Answer 1

ΔT = imK

ΔT = change in temperature = ?

i = vant Hoff factor = 1 for sucrose, a non electrolyte

m = molality = moles/kg solvent = 1 mol/1 kg = 1 molal

K = freezing point constant for water = 1.86^o/m

ΔT = (1)(1)(1.86) = 1.86 degrees

Final freezing point of the solution = -1.86 degrees C assuming the normal freezing point is 0 degrees C