If m<ECD is six less than five times m<BCE, and m<BCD=162°, then find m<BCE and m<ECD

Answer 1

Draw and label a diagram!!

m∠ECD + m∠BCE = m∠BCE

m∠ECD = 5 m∠BCE

5 m∠BCE + m∠BCE = m∠BCD

5 m∠BCE = m∠BCE

5 m∠BCE = 162°

Can you complete and answer?