How much energy is needed to heat up 240mL of ice cold water to body temperature after drinking it ?

Answer 1

You need the specific heat of water which is 4.284 J/gdeg

Then use q = mCΔT

q = heat = ?

m = mass = 240 g assuming a density of 1 g/ml for ice water

C = specific heat = 4.184 J/g/deg

ΔT = change in temperature = 37 - 0 = 37 degrees assuming body temperature is 37⁰C and ice warer is 0⁰C

q = (240g)(4.184 J/g/deg)(37 deg) = 37,154 J = 37 kJ (2 sig figs)