Let BK = h, AK = y and BK=x
AC=20 (this is a 3-4-5 right triangle)
h2 + y2 =144
h2 + x2 = 256
Subtract
x2 - y2 = 112
(x+y)(x-y)=112
x+y =20
Divide
x-y=5.6
x+y=20
2x =25.6
x=12.8
y=7.2
John A.
asked 09/16/19Given: △ABC, m∠B=90°
AB=12, BC=16,
BK
⊥
AC
.
Find: AC and BK.
Let BK = h, AK = y and BK=x
AC=20 (this is a 3-4-5 right triangle)
h2 + y2 =144
h2 + x2 = 256
Subtract
x2 - y2 = 112
(x+y)(x-y)=112
x+y =20
Divide
x-y=5.6
x+y=20
2x =25.6
x=12.8
y=7.2
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