J.R. S. answered 09/16/19
Ph.D. University Professor with 10+ years Tutoring Experience
For this type of problem, you can generally use the Henderson Hasselbalch equation:
pH = pKa + log [salt]/[acid]
pH = 5.00
pKa = -log Ka = -log 1.74x10-5 = 4.76
log [salt]/[acid] = ?
0.2 mol/L x 0.5 L = 0.1 moles of salt (NaAc) present, so we need to solve for log (0.1/x)
5.00 = 4.76 + log (0.1/x)
log (0.1/x) = 0.24
0.1/x = 1.74
x = 0.057 moles acid need to be added
To find the volume of 15.4 M acetic acid...
15.4 mole/L (x L) = 0.057 moles
x = 0.00370 L = 3.7 mls of acetic acid need to be added (this assumes we neglect the small change in volume from 500 mls to 503.7 mls)