Patrick B. answered 09/14/19
Math and computer tutor/teacher
(a) 95% of the data is within 2 standard deviations of the mean
(b) Per Chebyshev, 1 - 1/k^2 = 1 - 1/(1.5)^2 = 1 - 1/2.25 = 1 - reciprocal(9/4) = 1 - 4/9 = 5/9
regardless of the distribution.
so 55 and 5/9 % of the data lies within 1/5 standard deviation of the mean
We cannot calculate probabilities without the mean AND assuming the gas prices are
normally distributed.
$3.43 was a price, but WAS IT THE MEAN????
Please repost