calculate the amount of CO2 ( in grams ) that could be produced from 76 g of C3H8?

Answer 1

First, let's write a correctly balanced equation for the formation of CO2 from C₃H₈:

C₃H₈ + 5O₂ ==> 3CO₂ + 4H₂O

Next, we can convert 76 g to moles:

76 g x 1 mole/44 g = 1.727 moles C₃H₈

From the stoichiometry of the balanced equation, 1 mole C₃H₈ produces 3 moles CO₂, thus...

1.727 moles C₃H₈ x 3 moles CO₂/mole C₃H₈ = 5.18 moles CO2 produced

mass of CO₂ = 5.18 moles CO₂ x 44 g/mole = 228 grams CO₂