Calculate the heat change in kilocalories for melting 120 g of ice at 0 ∘C.

Question

Express your answer as a positive value using two significant figures and include the appropriate units.

Answer 1

To melt the ice at 0ºC, you use the ∆H_fusion for water, which is 334 J/g

120 g x 334 J/g = 40,080 J = 40.080 kJ = 40. kJ (to 2 significant figures)