Find An Equation Of The Circle...

Question

Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 2) and Q(6, 8).

Answer 1

The diameter of the circle is sqrt{ (-2-6)² + (2-8)² } = sqrt(64+36) = 10

The center of the diameter is at point (2, 5)

So, the equation of the circle is (x-2)² + (y-5)² = 25