Chemistry help with equilibrium

Question

2A(g) <-> B(g) kp= 3.51x10^-5

if a sample of A(g) at 2.10 atm is heated to 500 K, what is the pressure of B(g) at equilibrium?

Please help I can’t geg the right answer.

Answer 1

2A == B Kp = 3.51x10^-5

2.1 .....0.....Initial

-2x....+x....Change

2.1-2x..x....Equilibrium

Kp = P_B/P_A² = 3.5x10^-5

3.51x10^-5 = (x)/(2.1-2x)²

Solve for x and that will be the pressure of B at equilibrium.