Patrick B. answered 09/11/19
Math and computer tutor/teacher
First of all the coordinates of the point on the triangle has negative coordinates. But the side measures are always positive, per the distance formula...
Second, if there is only one negative, just move it to the top... NEVER PUT an extra negative sign
where it does not belong!!! If there is only one negative sign, it CANNOT be in BOTH!!!
Now for the problem:
sin T = -1/sqrt(5) = -sqrt(5)/5 <--- rationalizes the denominator....
Next you need to remember the mnemonic device: ASTC "All students take calculus" or
"Add sugar to coffee"
A: all trig functions are positive in quadrant 1
S: sine is positive in quadrant 2
T: tangent is positive in quadrant 3
C: cosine is positive in quadrant 4
Here, the sine and tangent are both negative, so that must be quadrant 4.
the inverse sine of sqrt(5)/5 is about 26.565+ degrees
so the angle in quadrant 4 is 360 - 26.565+ = 333.435-