chemistry question

Question

How many grams of CaSO4 will precipitate if 5.64 mL of 0.0986 M H2SO4 is mixed with 25.00 mL of 0.050 M Ca(OH)2?

Answer 1

H₂SO₄(aq) + Ca(OH)₂(s) ==> CaSO₄(s) + 2H₂O(l)

moles H₂SO₄ present = 5.64 ml x 0.0986 mmol/ml = 0.5561 mmol = 0.0005561 moles

moles Ca(OH)₂ present = 25 ml x 0.05 mmol/ml = 1.25 mmol = 0.00125 moles

Limiting reactant = H₂SO₄

moles CaSO₄ formed = 0.0005561 moles H₂SO4 x 1 mole CaSO₄/mole H₂SO₄ = 0.0005561 moles CaSO₄

mass CaSO₄ = 0.0005561 moles x 136.1 g/mole = 0.0757 g CaSO₄