J.R. S. answered 09/09/19
Ph.D. University Professor with 10+ years Tutoring Experience
Exp 1 and 2: zero order in
Exp 1 and 3: first order in B
Exp 3 and 4: second order in C
rate = k[B][C]2
k = rate/[B][C]2 = 2x10-3/(0.2)(0.4)2
k = 0.0625 M-2s-1