The perimeter of the rectangular playing field is 548 yards. The length of the field is 6 yards less than quadruple the width. What are the dimensions of the playing​ field?

Answer 1

Width = 56 yards

Length = 218yards

Perimeter = 2(Width) + 2(Length)

P = 2W + 2L

P = 548

L = 4W - 6

548 = 2W + 2(4W - 6)

Divide both sides by 2

274 = W + 4W - 6

Combine like terms

274 = 5W - 6

Add 6 to both sides

280 = 5W

Divide both sides by 5

56 = W

4W - 6 = L = 4(56) - 6 = 224 - 6 = 218

Checking

548 = 2(56) + 2(218)

548 = 112 + 436

548 = 548

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