Find the area of rectangle BCEF . Round the area to the nearest whole number, if necessary.

Question

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Answer 1

Each square is 1*1.

The diagonal length is 1^2+1^2=c^2 (a^2+b^2=c^2) only for rt/tri. So "c"=2^.5=1.414.

The size of the rectangle is: 4*2*1.414=11.314.

The triangles are: (3*2+2*2*1.414)/2=7.07

+11.34

=18.41sq

Answer 2

To find the area of the rectangle, you need the length (BC or EF) and the width (CE or FB).

So if we find the distance between B and C, that will give us the length.

And we will need the distance between C and E to know the width.

B(0,3) and C(4, -1) Dist = sqrt[ (4-0)² + (-1-3)² ] = sqrt(32) = 4√2 approx = 5.657 = length

C(4, -1) and E(2, -3) Dist = sqrt[ (2-4)² + (-3 - (-1) )² ] = sqrt(8) = 2√2 approx = 2.828 = width

Area = (length)(width) = (4√2)(2√2) = 8√4 = 8*2 = 16

Area is 16 square units.