Arthur D. answered 09/06/19
Tutor
5.0
(254)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
use the distance formula, √[(x2-x1)^2+(y2-y1)^2], for XY, YZ and ZX
you can do the math...
XY=√25=5
YZ=√20=2√5
ZX=√25=5
P=5+5+2√5
P=10+2√5
P=10+4.472
P=14.47
Ian O.
Thank you!09/06/19