Chase is 184 miles away from Spencer. They are traveling towards each other. If Spencer travels 7 mph faster than Chase and they meet after 8 hours, how fast was each traveling?

Answer 1

If x = the speed of Spencer, and y = the speed of Chase, then:

x = y + 7 (because Spencer is travelling 7 mph faster than Chase)

Also, both Chase and Spencer travel for 8 hours and cover 184 miles of distance in total. Since distance = velocity*time, then:

184 miles = 8x + 8y

184 = 8*(x+y)

23 = x + y

And since x = y+7 (as shown above), then:

23 = (y+7)+y

23 = 2y + 7

y = 8 mph = speed of Chase

Since Spencer travelled 7 mph faster than Chase, then x = 15 mph = speed of Spencer.

Answer 2

Initial distance d = 184 miles. S=Spencer travels 7 mph faster than C=Chase (S=C+7). They meet after 8 hours.

In 8 hours, S+C together travel at a rate of 184/8 = 23 mph.

C+7 + C = 23

2C = 23-7

2C = 16

C = 8 mph.

S = C=& = 8+7 = 15 mph

15+8 = 23 mph combined.

Answer 3

r is the rate of speed for Chase.

distance = rate x time

184 = (r + r+7) * 8

184 = (2r+7)*8

184 = 16r + 56

128 = 16r

r=8

CHASE 8 mph

SPENCER 15 mph

check:

8 * 8 + 15*8 =

64 + 120 =

184