The length of a rectangle is three times its width The area of the rectangle is 108 cm to second power find its perimeter

Answer 1

rectangle perimeter = 2(W + L ) lets call width=W and length =L

rectangle area =L*W solve for the two equation since L=3*W we can substitute in both equations and we get

rectangle perimeter = 2(W + 3*W)= 8W.

rectangle area = 3*W*W= 3W² =108cm² solve for W we get W=6cm.

therefore the rectangle perimeter is equal 8W=8*6=48cm.

Hope it helps :)

Answer 2

L = 3W

L*W = 108

3W*W = 108

W² = 36

W = 6

L = 3W = 18

Perimeter = 2*(L + W) = 2*24 = 48