chemistry homework

Question

3H2(g) + N2(g)→2NH3(g)

How many moles of NH3 can be produced from 29.0 mol of H2 and excess N2?

Answer 1

3H₂(g) + N₂(g)→2NH₃(g) ... balanced equation

moles H₂ present = 29.0 moles

moles NH₃ that can form = 29.0 moles H₂ x 2 moles NH₃/3 moles H₂ = 19.3 moles NH₃ (to 3 sig. figs.)