J.R. S. answered 09/01/19
Ph.D. University Professor with 10+ years Tutoring Experience
36400 cal/pint x 0.7 pints = 25480 cal
25480 cal x 4.184 J/cal = 106,608 J = 107 kJ
Jada H.
asked 08/31/19Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has prepared Ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.700 pint of room temperature water, how many kilojoules of heat energy will have been absorbed by the water at the moment it begins to boil?
J.R. S. answered 09/01/19
Ph.D. University Professor with 10+ years Tutoring Experience
36400 cal/pint x 0.7 pints = 25480 cal
25480 cal x 4.184 J/cal = 106,608 J = 107 kJ
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