Mark M. answered 08/24/19
Retired Math prof with teaching and tutoring experience in trig.
sin(2θ) = 2sinθcosθ
So, sin(x/2)cos(x/2) = (1/2)sinx
1 - 2sin2θ = cos(2θ)
So, 1 - 2sin2(x/2) = cosx
Therefore, sin(x/2)cos(x/2)(1 - 2sin2(x/2)) = (1/2)sinxcosx = (1/4)sin(2x)