Cd=2×,bd=3x+4,bc=2x-1

Answer 1

d = 2^x/c

b(2^x/c) = 3x+4

b = (3x+4)*c/2^x

(3x+4)*c^2/2^x= 2x-1

(3x+4) = (2x-1)(2^x) * c^2

(3x+4)/(2x-1)*(2^x) = c^2

c = sqrt( (3x+4)/(2x-1)* (2^(x))