Since ΔABC ≅ ΔEDF, EF ≅ AC, ED ≅ AB, and DF ≅ BC
Length of EF = √[(3-(-1))2 + (1-1)2] = 4
Makenna W.
asked 08/21/19Since ΔABC ≅ ΔEDF, EF ≅ AC, ED ≅ AB, and DF ≅ BC
Length of EF = √[(3-(-1))2 + (1-1)2] = 4
Sam Z. answered 08/21/19
Math/Science Tutor
What's the scale of the triangles? I know nothing about EDC.
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