Patrick B. answered 08/24/19
Tutor
4.7
(31)
Math and computer tutor/teacher
540 = (r+s)*3 = (r-s)*6
3r + 3s = 6r - 6s
9s = 3r
3s = r
540 = (3s+s)*3
540 = 12s
s = 45
r=135
Charlotte G.
asked 08/20/19A certain aircraft can fly 540 miles with the wind in 3 hours and travel the same distance against the wind in 6 hours.
Patrick B. answered 08/24/19
Math and computer tutor/teacher
540 = (r+s)*3 = (r-s)*6
3r + 3s = 6r - 6s
9s = 3r
3s = r
540 = (3s+s)*3
540 = 12s
s = 45
r=135
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