The chances that it will rain exactly 2 out of 3 days is:
NCR(p)R(q)(N-R)
where
C = Combination symbol
N = total number of days
R = Number of rain days
p = probability that it will rain
q = probability that it will not rain
So,
3C2(7/10)2(3/10)(3-2) = (3!/(2!(3-2)!))(7/10)2(3/10)1 = .441
or
There is a 44.1% chance that it will rain 2 of the 3 days