Jim S. answered • 08/18/19

Physics (and math) are fun, really

Hi,

If you factor an n^{2} out of the numerator an denominator you have

Num: n^{2} *(1/n^{2} + 3/n +4)

Denom: n^{2} *(5/x^{2 } + 6/n + 2)

when you form the ratio the n^{2} 's cancel.

Now take the lim as n→∞ and all but the last term →0 and you are left with ln(4/2) =ln(2)

Does that make sense?

Jim