How to write an equation with -2/3 and (10,-3)

Answer 1

I am assuming from the information you gave that the slope of the line should be -2/3 and that the line passes through the point (10,-3).

There are several ways to approach this problem. I would recommend using the point-slope form of the equation of a line:

y-y₁=m(x-x₁)

Plug in the slope for m, and plug in the x-value of the point, 10, into x₁ and the y-value of the point, -3, into y₁.

This will give you:

y+3= -2/3(x-10)

Simplify:

y+3 = -2/3x + 20/3

y = -2/3x + 20/3 - 3

y = -2/3x + 20/3 - 9/3

Final Answer:

y = -2/3x + 11/3

Hope this helps!