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Kripa M.

asked • 01/15/15

Write an equation of the line that is the perpendicular bisector of the line segment.

It must have endpoints (3,-1) and (3,5). 

Mark M.

Which line has the specified endpoints? The line or the bisector?
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01/15/15

Fartash Y.

the equation of the line is: x=3(because x is constant) therefore the perpendicular line must be y=a now we have to find a.now the bisector is perpendicular to the line and pass throw the midpoint of the line.therefore a must be the midpoint of the line which is a=(y1+y2)/2=(5-1)/2=2 therefore your answer is   y=2.

 
 
 
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01/18/15

1 Expert Answer

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Tim T. answered • 06/16/20

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Math: K-12th grade to Advanced Calc, Ring Theory, Cryptography
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Greetings! Lets solve this shall we ?


So, we must find the equation of a line that must possess these end points. So, we pull out the equation of the slope to obtain m = (5-(-1)) / (3-3) = 6/0. This represents the line having infinite vertical rise and no horizontal shift. Therefore, the equation of the line that has the given endpoints is x = 3.


I hope this helped!

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