Shailesh K. answered 08/12/19
MS in Electrical Engineering with 8+ years of teaching experience
Given f(x) = ln x Therfefore, f(1) = 1/x , f(2) = -1/x2, f(3) = 2/x3, and f(4) = -6/x4 Here f(i) is ith derivative f(x)
Taylor's series centered at 9, a = 9.
f(x) = ln x = ln 9 + (x-9)×1/9 + (-1)1 × (x-9)2/(2!×9^2) + (-1)2 ×2 (x-9)3/(3!×9^3) + (-1)3 × 6 (x-9)4/(4!×9^4)
= 2.197 + (x-9)/9 = (x-9)2/(2×9^2) + (x-9)3/(3×9^3) - (x-9)4/(4×9^4)
Cn = f(n)(a)/n! gives C0 = 2.197, C1 = 1/ (1!×9^1), C2 = 2/(2!×9^2), C3 = 2/(3!×9^3), and C4 = 6/(4!×9^4)
Radius of convergence R = 9
from x= _9_ left end, included (yes or no) Yes
to x=_9_ right end, included (yes or no) Yes


Shailesh K.
08/13/19
William P.
08/12/19