how would i solve this

Question

the length of a rectangle is 3 cm greater then it’s width. the perimeter is 24 cm. find the dimensions of the rectangle.

Answer 1

Let's say that the length of the rectangle = L; and the width of the rectangle = W

The first sentence says, "the length of a rectangle is 3 cm greater than its width"

Translated, we can say L = W + 3.....(1)

Now, when it says, "...the perimeter is 24"

Well, the perimeter of a rectangle is

P = 2L + 2W so,

24 = 2L + 2W

Notice that the equation above can be divided by 2 to give us

12 = L + W.......(2)

Now using (1) we can substitute W + 3 in place of L, giving us

12 = (W + 3) + W

12 = 2W + 3

9 = 2W

W = 9/2 = 4.5 cm

Thus, L = W + 3

L = 4.5 + 3 = 7.5 cm

So the dimensions of the rectangle is 4.5 cm x 7.5 cm.

Hope this helps

Mr. K

Answer 2

Length + width = half the perimeter = 24/2 = 12

L=W+3 L+W=12 W+3+W=12 2W=9 W=9/2 = 4 1/2 cm

L=9/2 + 3 = 7 1/2 cm

check the answers

7 1/2 is 4 1/2 + 3

2L + 2W = 2(15/2)+2(9/2)=15+9=24

Answer 3