Kevin C. answered 08/09/19
Successful Math Tutor -- Recently retired high school math teacher
z=rcisθ (rcisθ)1/n=r1/n(cis((θ+(360k)/n)) k=0, 1, 2, ... n-1
First find (θ/n) and (360k)/n 240/3=80 and 360(0)=0, 360(1)/3 = 120 and 720/3 = 240
So to find (27cis240)1/3, take 271/3=3 and find cos80 and sin80, cos(80+120) and sin(80+120), cos(80+240) and sin(80+240).
z1/3=3cis(80), 3cis(200), and 3cis(320).
(Notice that the angles 80°, 200°, and 320° are all 120° apart)
z3=r3cis(3θ) so (3cis(80))3=33cis(240)
Hope this helped.