log4(x+2) + log4(x-4) = 2
log4[(x+2)(x-4)] = 2
(x+2)(x-4) = 42
So, x2 - 2x - 24 = 0
(x - 6)(x + 4) = 0
x = 6 or x = -4
-4 is extraneous, so x = 6.
Stephane-Bakardi F.
asked 08/01/19log4 (X+2)+log4(x-4)=2?
log4(x+2) + log4(x-4) = 2
log4[(x+2)(x-4)] = 2
(x+2)(x-4) = 42
So, x2 - 2x - 24 = 0
(x - 6)(x + 4) = 0
x = 6 or x = -4
-4 is extraneous, so x = 6.
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Stephane-Bakardi F.
thank you08/02/19