The slope would be (5-8)/(6-3) = -3/3 = -1 The point slope form of the equation is
y-8 = -1(x-3) or y-8 = -x + 3 Then rearranging we have y = -x + 11
Cristian T.
asked 07/26/19what is the slope-intercept form of the equation of the line that contains the points (3,8) and (6,5)
The slope would be (5-8)/(6-3) = -3/3 = -1 The point slope form of the equation is
y-8 = -1(x-3) or y-8 = -x + 3 Then rearranging we have y = -x + 11
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