Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using the standard thermodynamic data in the tables linked above..

Question

Consider the reaction

4HCl(g) + O₂(g)2H₂O(g) + 2Cl₂(g)

Using the standard thermodynamic data in the tables linked above, calculate G for this reaction at 298.15K if the pressure of each gas is 14.28 mm Hg.

ANSWER: ______  kJ/mol

Answer 1

You didn't include the data from the table, however, ...

∆G_rxn = ∆Gº + RT ln Q

Look up or calculate ∆Gº as ∑∆G_products - ∑∆G_reactants

R = 8.314 J/mol K

T = 298.15K

Q = (PH₂O)²(PCl₂)²/(PHCl)⁴(O₂) Convert 14.28 mm Hg to atm by dividing by 760 = 0.0188 atm

Q = (0.0188)²(0.0188)²/(0.0188)⁴(0.0188)

Plug in the values and solve for ∆G_rxn