There are two aircraft​ carriers, A and​ B, and carrier A is longer in length than the carrier B. The total length of these two carriers is 2178 ft, while the difference of their lengths is only 10 ft

Question

A) Find the length of each carrier.

B) If a football field has a length of 100 ​yards, determine the length of carrier A in terms of the number of football fields.

Answer 1

Two equations and two unknowns

A + B = 2178 feet

A - B = 10 feet

Solve for A (or B) in one of the two equations and plug it into the other. For example,

A - B = 10

A = 10 + B

So A + B = 2178

(10 + B) + B = 2178

10 + 2B = 2178

2B = 2178 - 10 = 2168

B = 2168/2 = 1084

Carrier A = 1094 feet

Carrier B = 1084 feet

If Carrier A = 1094 feet and there are 3 feet per yard,

(1094 ft)(1 yd/3 ft)(1 football field/100 yds) = 3.65 football fields

So Carrier A is 3.65 football fields long.

Answer 2

A+B=2178

A-B=10

2A = 2188 and A = 1094 so that B= 1084

Divide A and B by 300 to get length in football fields.