Mark M. answered 07/23/19
Retired Math prof with teaching and tutoring experience in trig.
1 + tan2x = sec2x
So, tan2x = sec2x - 1
Thus, 1 - tan2x = 1 - (sec2x - 1) = 2 - sec2x
Rahma E.
asked 07/23/19Why can't we say that as 1+sec^2x=tan^2x that 1-tan^2x=-sec^2x?
Edit: Here I made a mistake
It is 1+tan^2x = sec^2x
So there isn't a really simple way to get 1-tan^2x.
Mark M. answered 07/23/19
Retired Math prof with teaching and tutoring experience in trig.
1 + tan2x = sec2x
So, tan2x = sec2x - 1
Thus, 1 - tan2x = 1 - (sec2x - 1) = 2 - sec2x
Stephen C. answered 07/23/19
SAT Math, Algebra, Trig, PreCalc Tutor
Well, if we add tan^2x + sec^2x to both sides of your 2nd equation, you get the first equation. So you can say it, and you will be correct. :-)
Rahma E.
Thank you! Although I wrote it wrong, you taught me a new way to check my answer.07/23/19
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Rahma E.
Thank you, your answer really helped me.07/23/19