J.R. S. answered 07/19/19
Ph.D. University Professor with 10+ years Tutoring Experience
You can use V1M1 = V2M2 for this problem.
(159 ml)(6.6 M) = (x ml)(0.35 M)
x = 2829 ml = 2800 ml = 2.8 L (2 sig figs)
Briana C.
asked 07/19/19What volume of 0.350 M HNO3 can be made from 150mL of 6.6 M HNO3?
J.R. S. answered 07/19/19
Ph.D. University Professor with 10+ years Tutoring Experience
You can use V1M1 = V2M2 for this problem.
(159 ml)(6.6 M) = (x ml)(0.35 M)
x = 2829 ml = 2800 ml = 2.8 L (2 sig figs)
Reka J. answered 07/19/19
Chemistry, Math, Biology, test prep
In dilution problems, the key is to remember that amt of solute in final more dilute solution remains same as in the original concentrated solution.
Moles of solute in concentrated initial solution = molarity of sol × liters of sol
6.6 × 0.15 L = 0.99 mole of HNO3
Now determine the volume of final solution using same no of moles in final solution which has the molarity of .350M
Volume = 0.99 moles÷.350M = 2.8 liters
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