How many grams of NO2 can be formed from the reaction between 28 grams of nitrogen and 64 gram of oxygen

Question

How many grams of NO2 can be formed from the reaction between 28 grams of nitrogen and 64 gram of oxygen

Answer 1

-Write a correctly balanced equation:

N₂(g) + 2O₂(g) ==> 2NO₂(g)

-Find the limiting reactant, if any:

moles N₂ present = 28 g x 1 mole N₂/28 g = 1.0 mole N₂

moles O₂ present = 64 g x 1 mole O₂/32 g = 2 mole O₂

Since the balanced equation shows you need 2 moles O₂ per 1 mole N₂, neither is in limiting supply, and thus, either reactant can be used to determine the mass of NO₂ that should be produced.

-Theoretical yield or NO₂ = 1.0 mole N₂ x 2 moles NO₂/mole N₂ x 46 g/mole NO₂ = 92 g NO₂