In triangle ABC,m<A=44°, m<B=48°, and a=25. Find "c" to the nearest tenth.

Question

A. 18.6

B. 48.1

C. 36.0

D. 52.6

Answer 1

Hello Shayla,

First, find the measure of angle C. That is, m∠C = 180° - 44° - 48° = 88°. Now you can use the Law of Sines to find c. We can write

c/(sin(C)) = a/(sin(A))

c/sin(88°) = 25/sin(44°), so

c = (sin(88°)·25)/sin(44°)

c ≅ 36.0 (rounded to the nearest tenth.)

Hope that helps!

William