In triangle ABC,m<A=27,c=14, and m<B=25. Find "a" to the nearest tenth.

Question

A. 9.9

B. 8.1

C. 6.2

D. 9.1

Answer 1

This problem uses the law of sines

sine A/a = sineB /b = sine C/c

A + B = 52. so C = 180 -(B+A) -= 128deg

So, sin 27 / 27 = sin 128 /c

Solving for c = 8.06 or 8.1 to the nearest tenth Answer is B