J.R. S. answered 07/11/19
Ph.D. University Professor with 10+ years Tutoring Experience
12.5 g C x 1 mole C/12.0 g = 1.042 moles C
1.042 moles C x 1 mole CH3CH2OH/2 moles C = 0.521 moles ethanol
0.521 moles ethanol x 46.07 g/mole = 24.0 g of ethanol contains 12.5 g of carbon