how many grams of methane are in the container?

Question

A 2.30 L container is filled with methane gas (CH4) at a pressure of 2600 mmHg and a temperature of 25 ∘C.

Answer 1

Given:

Volume = V = 2.30 L

Pressure = P = 2600 mm Hg x 1 atm/760 mm = 3.42 atm

Temperature = T = 25ºC + 273 = 298K

Asked for:

Find grams of methane. To answer this, we first must find moles of methane.

Use the ideal gas equation PV = nRT and solve for n(moles)

n = PV/RT = (3.42 atm)(2.30 L)/(0.0821 Latm/Kmol)(298K)

n = 0.322 moles methane

molar mass methane = 16 g/mole

grams methane present = 0.322 moles x 16 g/mole = 5.15 g