what is the volume in milliliters of krypton?

Question

A 30.0 g sample of krypton has a temperature of 24 ∘C at 575 mmHg .

Answer 1

Atomic mass of krypton (Kr) = 83.798 g/mole

To find the volume of 30.0 g, we can use the ideal gas law: PV = nRT

P = pressure = 575 mm Hg (converted to atmospheres, we have 575 mm x 1 atm/760mm = 0.7566 atm)

V = volume = ?

n = moles = 30.0 g x 1 mole/83.798 g = 0.3580 moles

R = gas constant = 0.0821 L-atm/K-mole (note the units of L, which is why we converted mm Hg to atm)

T = temperature in K = 24ºC + 273 = 297K

PV = nRT

V = nRT/P = (0.3580 mol)(0.0821 L-atm/K-mol)(297K)/0.7566 atm

V = 11.538 L

Since they want the volume in mls, we convert 11.538 L x 1000 ml/L = 11538 mls = 11,500 mls (3 sig. figs.)