Since e^-5t is never zero, the times when y = 0 will be when sin(2π t) is zero. This will happen at
t =0, t = 1/2, t = 1, t = 3/2 etc
Krista P.
asked 07/09/19Find the first four times when the spring is at its equilibrium position, y = 0, and starting at time t = 0.
y = 4 e^−5t sin 2πt
Since e^-5t is never zero, the times when y = 0 will be when sin(2π t) is zero. This will happen at
t =0, t = 1/2, t = 1, t = 3/2 etc
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