
Claytonia B. answered 07/09/19
Charlotte's Best Math Tutor
Hello James! I will do my best to answer the questions above. This question is related to a normal distribution. I would normally answer this using a TI-84 calculator, so I will do that first, then discuss how to do it by hand.
First, you must take the population information given and convert it to a sampling distribution. As such, the population mean of 15,572 would also be the sample mean. μ=x-bar. Then to convert the population standard deviation to a sample standard deviation, we use the formula σ/√n . So, 3150/√50 = 445.477.
Using the TI-84 Calculator
Now, in the TI-84 calculator, you hit 2nd VARS, Option #2 (normalcdf). Since the questions asks for the probability that the mean is less than 15,000, this is a left tail question. Thus the lower limit is negative infinity which we represent at -1E99 (the E is 2nd then the comma button above the 7). The upper limit is 15000, the mean is 15572 and the standard deviation is 445.477. It will look like this: normalcdf(-1E99, 15000, 15572, 445.477). Execute that, and you will get the answer.
By Hand
To do this by hand, you will convert the 15000 into a Z-score using the formula z = (x-µ)/(σ/√n). So it will be (15000-15572)/(3150/√50) = -572/445.477 = -1.28. You will then use the Standard Normal Distribution table found in your book to look up that z-score.
Now, please let me know what answer you get after following these steps.

Claytonia B.
My answer is slightly different from yours, so please double check, and be sure not to round off too much or too soon. I have 9.96% for 50 students and 34.24% for 5 students.07/11/19